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d-block redoxCrystal field theoryHigh-spin vs low-spinOxygen releaseVoltage ceiling

The anode side of this story is about one element. The cathode side is about a whole block of the periodic table, and the reason is a single requirement that main-group elements physically cannot satisfy: a cathode must accept and release electrons reversibly, thousands of times, at high potential, without falling apart.

3.1The five jobs a cathode has to do

  • Accept and release Li⁺ reversibly — a structural requirement.
  • Accept and release electrons reversibly — a redox requirement.
  • Do the second at a high potential, because cell voltage is cathode potential minus anode potential.
  • Conduct electrons well enough to work at all.
  • Not fall apart when half its lithium has been removed.

Requirement two is where the d-block stops being one option among several and becomes mandatory.

3.2Variable oxidation state — the d-orbital advantage

Oxidation state is the notional charge an atom would carry if all its bonds were fully ionic. A redox couple is a pair of oxidation states an element cycles between, such as Co³⁺/Co⁴⁺.

Main-group elements have essentially fixed oxidation states. Sodium is always +1, magnesium always +2, aluminium always +3. Removing another electron means breaking into a filled shell, which is energetically prohibitive — so they cannot cycle.

Transition metals have partially filled d orbitals. The 3d and 4s levels sit close in energy, and the d orbitals are relatively contracted and poorly shielding, so successive ionisation energies rise gently rather than sharply. The result is that manganese alone accesses +2, +3, +4, +6 and +7.

Important

This is the entire reason cathodes are made of d-block metals. They can absorb an electron on discharge and release it on charge, thousands of times, without structural collapse. Nothing in the s-block or p-block can.

3.3Crystal field theory — where the voltage comes from

Crystal field theory models what happens when the five d orbitals of a transition metal ion — degenerate, meaning equal in energy, when isolated — are surrounded by ligands, here O²⁻ ions. Orbitals pointing at the ligands are destabilised by electrostatic repulsion; those pointing between them are not.

In octahedral coordination — six oxygens around one metal, the standard geometry in a layered oxide — the five orbitals split into two sets:

  • t₂g (d_xy, d_xz, d_yz) — pointing between the oxygens, and therefore lower in energy.
  • e_g (d_z², d_x²−y²) — pointing at the oxygens, and therefore higher in energy.

The energy gap between them is Δ_o, the octahedral crystal field splitting parameter.

Why this matters

Δ_o sets the redox potential. The energy of the d level being emptied determines how much energy is released per electron, and therefore the voltage.

Where the common couples sit

Redox coupleHostApproximate potential vs Li/Li⁺
Co³⁺/Co⁴⁺LiCoO₂ layered~3.9 V
Ni³⁺/Ni⁴⁺LiNiO₂ layered~3.8 V
Mn³⁺/Mn⁴⁺LiMn₂O₄ spinel~4.1 V
Fe²⁺/Fe³⁺Simple oxide~3.0 V
Fe²⁺/Fe³⁺LiFePO₄ olivine3.45 V — see chapter 5
MO₆ OCTAHEDRONMsix O²⁻ ligandsFREE ION5 degenerate d orbitalsOCTAHEDRAL FIELDe_gt_2gpoint AT ligandspoint BETWEEN ligandsΔ_oTWO CONSEQUENCESCo³⁺ — LOW SPIN d⁶t₂g⁶ e_g⁰compact, rigidr = 54.5 pm→ no cation mixing, fast Li diffusionMn³⁺ — HIGH SPIN d⁴t₂g³ e_g¹DEGENERATE e_g→ Jahn–Teller distortion (Plate 13)Δ_o SETS THE REDOX ENERGY, AND THEREFORE THE VOLTAGE: LiCoO₂ ≈ 3.9 V · LiNiO₂ ≈ 3.8 V · LiMn₂O₄ ≈ 4.1 V vs Li/Li⁺
Figure 3.1Three things follow from Δo. First, it sets the energy of the d level being emptied, and therefore the cell voltage. Second, it decides high-spin versus low-spin, which sets ionic radius and structural stability — low-spin Co³⁺ is compact and rigid, which is why cobalt has been so hard to eliminate. Third, an unevenly occupied eg set triggers the Jahn–Teller distortion that limits manganese spinel.

3.4High-spin, low-spin and structural stability

Δ_o also determines whether d electrons pair up in the lower set or spread out to maximise unpaired spins. If Δ_o exceeds the energy cost of pairing two electrons in one orbital, they pair — low-spin. If not, they spread — high-spin.

In plain English

Spin state is not an abstraction. It sets ionic radius, and ionic radius sets structural stability. Low-spin Co³⁺ is t₂g⁶ — all six electrons paired in the low set — which makes it compact at 54.5 pm and rigid. That is why LiCoO₂ is the best-behaved layered oxide structurally, and a large part of why cobalt has been so hard to eliminate.

The same logic runs the other way for manganese. High-spin Mn³⁺ is d⁴ with a single electron in the doubly degenerate e_g set, and that unequal occupancy triggers the Jahn–Teller distortion that is the subject of chapter 4.

3.5The oxygen 2p band and the voltage ceiling

In a solid, discrete metal d levels broaden into bands. The Fermi level is the energy up to which states are filled.

Charging a cathode means lowering its Fermi level, because you are removing electrons. Lower it far enough and it drops below the top of the oxygen 2p band — and at that point you begin pulling electrons off oxygen rather than off the metal.

Important

Oxidised O²⁻ is unstable. It can dimerise into peroxide-like species and it can leave the lattice as O₂ gas. That released oxygen is what makes an overcharged NMC cell burn so violently: the cell contains its own oxidiser, so excluding air does not stop it.

Technical framing

This is the fundamental voltage ceiling of oxide cathodes, and it is a periodic-table property — it is set by where the metal d band sits relative to the O 2p band.

Nickel-rich cathodes have their nickel d band closer to the O 2p band, which is exactly why higher nickel content delivers higher capacity and lower thermal stability. It is one trade-off, not two independent facts, and no amount of pack engineering separates them.

Quick check: test yourself

1.Why can’t aluminium be a cathode redox centre even though it is cheap, light and abundant?

Show answer
Because Al³⁺ has a closed [Ne] shell with no accessible d electrons, so its oxidation state is fixed. Removing another electron means breaking into a filled shell. It cannot cycle, which is why in NCA it acts as a structural dopant contributing zero capacity.

2.Why does more nickel mean both more capacity and more danger?

Show answer
Because both come from the same fact — the nickel d band sits closer to the oxygen 2p band. That allows more electrons to be extracted (capacity) but means the Fermi level reaches the O 2p band sooner on charge, triggering oxygen release (thermal instability). One trade-off, not two.

3.What does low-spin Co³⁺ actually buy a layered oxide?

Show answer
Compactness and rigidity. All six d electrons paired in the t₂g set gives a small 54.5 pm ion with a strong preference for the octahedral metal site, so layer spacing stays stable and almost no cation mixing with lithium occurs.

Chapter summary

Frequently asked questions

Why are lithium-ion cathodes made from transition metals?+

Because a cathode must accept and release electrons reversibly at high potential, thousands of times, without structural collapse — and only partially filled d orbitals allow that. Main-group elements have essentially fixed oxidation states: removing another electron means breaking into a filled shell, which is energetically prohibitive. In transition metals the 3d and 4s levels are close in energy and the d orbitals are contracted and poorly shielding, so successive ionisation energies rise gently rather than sharply. Manganese alone accesses +2, +3, +4, +6 and +7.

What is crystal field splitting and how does it set battery voltage?+

In an isolated ion the five d orbitals have equal energy. Surround the metal with six oxygens in octahedral coordination and the orbitals pointing directly at the oxygens (the e_g set) are pushed higher in energy by electrostatic repulsion, while those pointing between them (the t₂g set) sit lower. The gap is Δ_o. The energy of the d level being emptied on charge determines how much energy is released per electron, and therefore the voltage — which is why Co³⁺/Co⁴⁺ sits near 3.9 V, Ni³⁺/Ni⁴⁺ near 3.8 V and Mn³⁺/Mn⁴⁺ in spinel near 4.1 V.

Why do nickel-rich cathodes release oxygen?+

Charging a cathode lowers its Fermi level by removing electrons. Lower it far enough and it drops below the top of the oxygen 2p band — at which point you begin pulling electrons off oxygen rather than off the metal. Oxidised O²⁻ is unstable, can dimerise to peroxide-like species and can leave the lattice as O₂ gas. Nickel-rich cathodes have their nickel d band closer to the O 2p band, which is exactly why more nickel means both higher capacity and lower thermal stability. It is one trade-off, not two independent facts, and it is why an overcharged NMC cell burns so violently: it contains its own oxidiser.

What does high-spin versus low-spin mean for a cathode?+

Whether d electrons pair up in the lower t₂g set or spread out to maximise unpaired spins, decided by whether Δ_o exceeds the electron pairing energy. It matters because spin state sets ionic radius, which sets structural stability. Low-spin Co³⁺ is t₂g⁶ — all six electrons paired in the low set — making it compact at 54.5 pm and rigid. That is why LiCoO₂ is the best-behaved layered oxide structurally, and a large part of why cobalt has been so hard to eliminate.

Reviewed by

SG

Sahil Goyal

Co-founder, Wingzman

LinkedIn
SG

Sourabh Goyal

Co-founder, Wingzman

LinkedIn

The Periodic Table of the EV is an original educational series on the materials science of electric vehicles. All values are standard-condition literature figures for representative materials, not measured data from a specific product, and sources differ on several of them. Always verify against the specific material datasheet in use before making design, purchasing or certification decisions.